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Check the picture below.

so from the picture we can see the period, we can also see it has an amplitude of 1, unchanged from its parent, and no horizontal or vertical shifts, so we can say the constants of C and D are the same as the parent's, of 0 and 0. Let's use the cos(x), and you're correct A = -1, let's find B.


\cfrac{4\pi }{3}=\cfrac{2\pi }{B}\implies 4\pi B=6\pi \implies B=\cfrac{6\pi }{4\pi }\implies B=\cfrac{3}{2} \\\\\\ ~\hfill~ {\Large \begin{array}{llll} y=-\cos\left((3x)/(2) \right) \end{array}} ~\hfill~

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