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A shipment of 10 computers contains 4 with defects. Find the probability that a sample of size 4, drawn from the 10, will not contain a defective computer,The probability is:

User Pshegger
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1 Answer

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ANSWER


P=(81)/(625)

Step-by-step explanation

There are 4 defects out of 10 total computers. This means that there are 6 computers without defects.

The probability that 1 computer selected will not be defective is the total number of non-defective computers divided by the total number of computers:


P(one-without-defect)=(6)/(10)

Therefore, if a sample of 4 computers is selected, the probability that the sample will not contain a defective computer is:


\begin{gathered} P=(6)/(10)\cdot(6)/(10)\cdot(6)/(10)\cdot(6)/(10)=((6)/(10))^4 \\ P=(81)/(625) \end{gathered}

User ApriOri
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