Question

A student was given a scholarship of 140 dollars in grade 10. In grade 11 they were given another scholarship worth more money and in grade 12 they were given yet another scholarship worth even more money. This student then was able to pay for 100% of their tuition at university with the scholarships received in high school. We need to find out how much this tuition was and we are given the following information: -the amount that was received in grade 12 was 60% of the total tuition paid for university -the amount received in grade 11 was 55% of that earned in grade 12 how much was the university tuition

Answer 1

Answer: The university tuition (T) is $2,000.

Explanation:

Given information:

In grade 12, the student received 60% of the total tuition, so the scholarship amount in grade 12 is 0.6T.

In grade 11, the student received 55% of what they earned in grade 12, so the scholarship amount in grade 11 is 0.55 * 0.6T.

To cover 100% of the tuition with these scholarships, the sum of all scholarships received in grades 10, 11, and 12 must be equal to the total tuition:

Scholarship in grade 10 + Scholarship in grade 11 + Scholarship in grade 12 = Total Tuition

140 + (0.55 * 0.6T) + 0.6T = T

Now, we can solve for T, the total tuition:

First, combine like terms:

140 + 0.33T + 0.6T = T

Next, subtract 0.33T from both sides to isolate T:

140 + 0.93T = T

Now, subtract T from both sides to solve for T:

0.93T - T = 140

0.07T = 140

Now, divide by 0.07 to find the value of T:

T = 140 / 0.07

T = 2000