Question

A sample of solid gold is heated with an electrical coil. If 23.0 Joules of energy are added to a 10.2 gram sample initially at 22.2°C, what is the final temperature of the gold?

Answer 1

To determine the final temperature of the gold, use the equation q = mcΔT and rearrange it to ΔT = q / (mc). Lookup the specific heat capacity of gold and plug it into the equation to find ΔT. Add ΔT to the initial temperature of the gold to get the final temperature.

Step-by-step explanation:

To determine the final temperature of the gold, we can use the equation q = mcΔT, where q is the energy added, m is the mass of the gold, c is the specific heat of gold, and ΔT is the change in temperature. First, we need to calculate the heat capacity of the gold using the equation q = mcΔT. Rearranging the equation, we have ΔT = q / (mc). Plugging in the values, we get ΔT = 23.0 J / (10.2 g * c), where c is the specific heat capacity of gold.

Since the specific heat capacity of gold is not provided, we need to look it up. The specific heat capacity of gold is 0.129 J/g °C. Plugging this value into the equation, we have ΔT = 23.0 J / (10.2 g * 0.129 J/g °C).

Simplifying the equation, we find that ΔT = 23.0 J / 1.3158 J/°C ≈ 17.49 °C. Therefore, the final temperature of the gold is approximately 22.2 °C + 17.49 °C = 39.69 °C.

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