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Work out the equation of the perpendicular to 2x 4y=3 with a y-intercept of -2

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Answer:

Explanation:

Lets assume that 2x 4y=3 is supposed to read 2x + 4y=3.

Lets rewrite the given equation in slope-intercept format of y=mx+b, where m is the slope and b is the y-intercept (the value of y when x is zero).

2x + 4y = 3

4y = -2x + 3

y = -(1/2)x + (3/4)

Lets call this line L. We'll say the new line is P

Any line perpendicular to L will have a slope that is the negative inverse of the reference line (L).

In this case, the negative inverse of -(1/2) is 2.

The new line, P, will have a slope of 2:

y = 2x+ b

Any value of b will result in a perpendicular line to L. But we want a line that has a y-intercept of -2, so lets make b equal to -2:

y = 2x - 2

This line will be perpendicular to L and pass through point (0,-2). See the attached graph.

Work out the equation of the perpendicular to 2x 4y=3 with a y-intercept of -2-example-1
User Rich Churcher
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