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how much pure acid should be mixed with 3 gallaons of a 40% acid solution in order to get a 90% acid solution?

User Eunhee
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1 Answer

7 votes

Answer:

To solve this problem, we can set up an equation based on the principle of the amount of acid:

Let's assume that "x" represents the amount of pure acid (100% concentration) that needs to be added to the mixture.

The equation can be set up as follows:

0.4 * 3 + 1 * x = 0.9 * (3 + x)

In this equation, the left side represents the total amount of acid in the initial mixture (3 gallons of 40% acid solution mixed with x gallons of pure acid), and the right side represents the desired amount of acid in the final mixture (90% acid solution).

Now, let's solve the equation:

0.4 * 3 + x = 0.9 * 3 + 0.9 * x

1.2 + x = 2.7 + 0.9x

Rearranging the equation:

x - 0.9x = 2.7 - 1.2

0.1x = 1.5

Dividing both sides by 0.1, we get:

x = 15

Therefore, you would need to mix 15 gallons of pure acid with 3 gallons of the 40% acid solution to obtain a 90% acid solution.

User Hellnar
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