Question

Solve the system of equations by graphing, substitution, or elimination. Write the ordered pairs in increasing order of

the x values, separated by a comma. If the system of equations is not solvable, enter no solution in the answer box
y=x+3
y = 2x²-x-1
(₁. Y₁). (x₂, y) =

Answer 1

Answer: No solution

Explanation:

Set both equation equal to each other

x+3 = 2x^2-x-1

2x^2+2 = 0

What ever x is either positive or negative the result of the function will always be positive. Since we have a +2 at the end.

We can try to solve the eqution to prove

2x^2+2 = 0

x^2 = -1

And x^2 could never be negative