Question

Can you do this for me?

Answer 1

Check the picture below.

`\begin{array}{llll} \textit{using the pythagorean theorem} \\\\ c^2=a^2+o^2\implies c=√(a^2 + o^2) \end{array} \qquad \begin{cases} c=\stackrel{hypotenuse}{l}\\ a=\stackrel{adjacent}{2}\\ o=\stackrel{opposite}{3} \end{cases} \\\\\\ l=√( 2^2 + 3^2)\implies l=√( 4 + 9 ) \implies l=√( 13 )\implies \boxed{l\approx 3.61~m} \\\\[-0.35em] ~\dotfill`

`\textit{Surface area of a Cone}\\\\ SA=\pi r√(r^2+h^2) + \pi r^2~~ \begin{cases} r=radius\\ h=height\\[-0.5em] \hrulefill\\ r=2\\ h=3 \end{cases}\implies SA=\pi (2)√(2^2+3^2)+\pi (2)^2 \\\\\\ SA=2\pi √(13)+4\pi \implies SA=2\pi (√(13)+2)\implies \boxed{SA\approx 35.22~m^2}`