Question

25. A body of mass 6 kg placed on a rough surface of friction co-efficient 0.6. If an external force is applied on the body, the body is on verge of sliding then, the frictional force acting on the body is (g=10 ms ²) (A) 30 N (C) 36 N (B) 32 N (D) 34 N​

Answer 1

C. 36

Step-by-step explanation:

To calculate the frictional force acting on the body, we need to consider the equation of motion for the body on the verge of sliding.

The equation is given by:

Frictional force (F) = Normal force (N) * Friction coefficient (μ)

The normal force (N) can be calculated as the product of mass (m) and gravitational acceleration (g):

N = m * g

Given:

Mass of the body (m) = 6 kg

Gravitational acceleration (g) = 10 m/s²

Friction coefficient (μ) = 0.6

Calculating the normal force:

N = 6 kg * 10 m/s²

N = 60 N

Now, we can calculate the frictional force:

F = N * μ

F = 60 N * 0.6

F = 36 N

Therefore, the frictional force acting on the body is 36 N (Option C).