Answer: y = 3x - 1, y + 1 = 3(x - 0), and -3x + y = - 1
Explanation:
We will write three different equations for this line. Note that the line intersects the y-axis at (0, -1) and has a slope of 3.
The first will be written in slope-intercept form. This takes the slope and the y-intercept in y = mx + b form, where m is the slope and b is the y-intercept.
y = mx + b
y = 3x - 1
Next, we will write a point-slope form equation. This is in the form y - y1 = m(x - x1) where (x1, y1) is a coordinate point on the graph and m is the slope.
y - y1 = m(x - x1)
y + 1 = 3(x - 0)
The last equation we will write is a standard-form equation. This is, put simply, slope-intercept form but instead of y being isolated, the constant is. A and B are coefficients, C is the constant, and x and y are variables.
Ax + By = C
-3x + y = - 1