Answer:
Explanation:
Point (6, -1) = (x, y)Slope = -3The proper linear equation is written in following form: y = mx + b (where m is slope, and b is y-intercept). Since we already have the slope, we need to find the y-intercept, bSo we plug in what we have:y = mx + b-1 = (-3)(6) + b, where we solve for b -1 = -18 + b b = 17Finally, the equation of the line that passes through point (6, -1) and has a slope of -3 is y = -3x + 17