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(-3,-2) equation quadratic

User Andyally
by
7.7k points

1 Answer

2 votes

Answer:


(-3)^2+2*(-3)*(3-√(2)) +(11+6√(2)) = -2

Explanation:

Let x be -3

so that:


x^(2) +2x k+k^2 = 9 - 6k + k^2=-2

k being a constant.

if we do the quadratic equation, we get that:


k_(1)=3-√(2);\\ k_(2)=3+√(2)

at the end we get the following expression:


(-3)^2+2*(-3)*(3-√(2)) +(11+6√(2)) = -2

User Sudhir Kumar
by
8.1k points

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