Question

A spring with a spring constant of 10 N/m is extended by 0.5 m . Calculate the Ee stored in the spring . What is the answer

Answer 1

Answer: 1.25 J.

Explanation:

The elastic potential energy (Ee) stored in a spring is given by the equation:

Ee = 1/2 * k * x^2

where:

k is the spring constant in N/m

x is the extension of the spring in m

In this case, k = 10 N/m and x = 0.5 m, so the elastic potential energy stored in the spring is:

Ee = 1/2 * 10 N/m * (0.5 m)^2 = 1.25 J

Therefore, the answer is 1.25 J.