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35 votes
35 votes
(300/m) + 44n m=15 n=4

User Hugo Delsing
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1 Answer

12 votes
12 votes

Solve (300/m) + 44n where m = 15 and n = 4


\begin{gathered} ((300)/(m))+44n \\ \text{Substitute for the values of m and n, and you have;} \\ ((300)/(15))+44(4) \\ 20+176 \\ 196 \end{gathered}

The solution to the expression is 196

User Jeff Dege
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