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I need help woth this asap i cant get it wrong

I need help woth this asap i cant get it wrong-example-1
User ChrisBellew
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1 Answer

7 votes
7 votes

The given equation is a quadratic equation. Recall, the standard form of a quadratic equation is expressed as

ax^2 + bx + c = 0

The given equation is

x^2 - 8x = - 128

By adding 128 to both sides of the equation, we have

x^2 - 8x + 128 = - 128 + 128

x^2 - 8x + 128 = 0

By comparing this equation with the standard form equation,

a = 1, b = - 8, c = 128

The formula for solving quadratic equations is expressed as


\begin{gathered} x\text{ = }\frac{-\text{ b }\pm\sqrt[]{b^2-4ac}}{2a} \\ By\text{ substituting the given values, it becomes} \\ x\text{ = }\frac{-\text{ - 8 }\pm\sqrt[]{-8^2-4(1*128)}}{2*1} \\ x\text{ = }\frac{8\pm\sqrt[]{64-512}}{2}\text{ = }\frac{8\pm\sqrt[]{-\text{ 448}}}{2}\text{ = }\frac{8\pm\sqrt[]{-64\text{ }*\text{ 7}}}{2} \\ x\text{ }=\frac{8\pm(\sqrt[]{-64)}*\sqrt[]{7}}{2} \\ \text{Note, }\sqrt[]{-\text{ 1}}\text{ = i} \\ \sqrt[]{-64}\text{ = 8i} \\ x\text{ = }\frac{8\pm8i\sqrt[]{7}}{2} \\ \text{Factoring out 2 in the numerator, we have} \\ x\text{ = }\frac{2(4\text{ }\pm4i\sqrt[]{7})}{2} \\ x\text{ = 4 }\pm4i\sqrt[]{7} \end{gathered}

Option A is correct

User Shivam Singla
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3.5k points