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What is the equation in slope intercept form that passes through the x axis at 6 and is perpendicular to the

equation represented by
y=-x-4
Oy=x +9
0y=x-9
Oy = -x + 6
Oy = x +4

User Chadoh
by
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1 Answer

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Final answer:

The equation in slope-intercept form that passes through the x-axis at 6 and is perpendicular to y = -x -4 is y = x.


Step-by-step explanation:

To find an equation in slope-intercept form that passes through the x-axis at 6 and is perpendicular to the equation y = -x - 4, we need to determine the slope of the given equation and then find the negative reciprocal. The given equation has a slope of -1, so the negative reciprocal is 1.

Since the line passes through the x-axis at 6, the y-intercept is 0. So the equation of the line in slope-intercept form, y = mx + b, becomes y = 1x + 0, which simplifies to y = x.

Therefore, the equation that satisfies the given conditions is y = x.


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