To solve the equation -2x + 3x - 1 = 0 using the quadratic formula, we first need to rearrange the equation in the form ax^2 + bx + c = 0.
In this case, we have -2x + 3x - 1 = 0. Combining like terms, we get x - 1 = 0.
Now, we can identify the values of a, b, and c for the quadratic formula: a = 1, b = -1, and c = 0.
The quadratic formula is given by:
x = (-b ± √(b^2 - 4ac)) / (2a)
Plugging in the values, we get:
x = (-(-1) ± √((-1)^2 - 4(1)(0))) / (2(1))
x = (1 ± √(1 - 0)) / 2
x = (1 ± √1) / 2
x = (1 ± 1) / 2
Simplifying further, we have two possible solutions:
x = (1 + 1) / 2 = 2 / 2 = 1
x = (1 - 1) / 2 = 0 / 2 = 0
Therefore, the solutions to the equation -2x + 3x - 1 = 0 are x = 1 and x = 0.
From the given options, the correct answer is D. x = 1 or x = -1.