Question

A gas with a volume of 3.0L at standard temperature and pressure is how many moles of that gas?

Answer 1

≈0.134

Step-by-step explanation:

To find the number of moles of a gas, you can use the Ideal Gas Law, which is given by the equation
`\(PV = nRT\)`, where:

- P is the pressure,

- V is the volume,

- n is the number of moles,

- R is the ideal gas constant, and

- T is the temperature.

At standard temperature and pressure (STP), the pressure P is 1 atmosphere, the temperature T is 273.15 K, and the ideal gas constant R is 0.0821 L·atm/(mol·K).

Given that the volume V is 3.0 L, you can rearrange the equation to solve for the number of moles n:

`\[ n = (PV)/(RT) \]`

Substitute the values:

`\[ n = \frac{(1\ \text{atm})(3.0\ \text{L})}{(0.0821\ \text{L*atm/(mol*K)})(273.15\ \text{K})} \]`

Calculate this expression, and you should get approximately 0.134 moles.

So, at standard temperature and pressure, a gas with a volume of 3.0 L would contain approximately 0.134 moles.