Question

In a commercial airliner, an empty water bottle contains about 500 mL of air. The air pressure at that altitude is 0.74 atm. What will the volume of the water bottle be after landing and reaching an air pressure of 1.0atm?

Answer 1

370 mL

Step-by-step explanation:

we can use Boyle's Law to solve this problem

Boyle's Law: P1V1 = P2V2

where:

P1 is the initial pressure

V1 is the initial volume

P2 is the final pressure

V2 is the final volume

We know the following values:

P1 = 0.74 atm

V1 = 500 mL

P2 = 1.0 atm

Step 1: Substitute the known values into Boyle's Law equation.

P1V1 = P2V2

(0.74 atm)(500 mL) = (1.0 atm)(V2)

Step 2: Solve for V2.

V2 = (P1V1) / P2

V2 = (0.74 atm)(500 mL) / (1.0 atm)

V2 = 370 mL