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Question Write an equation of the line passing through the point A(−1, 5) that is perpendicular to the line y = 17x+4 . y = '

User Dan Blows
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1 Answer

5 votes

Answer:
y = -(1)/(17)x + (84)/(17)

Explanation:

Find a slope perpendicular to the equation
y = 17x + 4 using the formula for finding a perpendicular slope (m₁ * m₂ = -1)


17 * m = -1


m = -(1)/(17)

Now that we have our slope, we can plug it into the slope-intercept formula to create our equation (we aren't done yet though).


y = mx + b

y = -(1)/(17) + b

We must find the y-intercept (the b variable) to complete our equation. We can do this by using the provided point (-1, 5) to do this. Simply take the x-coordinate -1 and y-coordinate 5 to substitute the values into the equation we made.


y = -(1)/(17)x + b


(5) = -(1)/(17)(-1) + b


5 = -(1)/(17)*-1 + b


5 = (1)/(17) + b


b = (84)/(17)

With the new y-intercept (b variable), we simply substitute this value back into our equation and we're done!


y = -(1)/(17)x + b\\y = -(1)/(17)x + ((84)/(17))\\\\y = -(1)/(17)x + (84)/(17)

User PereG
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