Question

Find the solutions to the equation below.

Check all that apply.
6x² + 7x50
□ A. X = -2
☐ B. X =
= 1/2
-IN 5
C. x = 5
□ D. X=-3
☐ Ex= 1/3
F. X = -1/3
-Im

Answer 1

Answer:Therefore, there are no solutions from the given options A, B, C, D, E, and F.

Explanation:

To find the solutions to the equation 6x² + 7x + 50, we can use the quadratic formula. The quadratic formula is given by:

x = (-b ± √(b² - 4ac)) / (2a)

In this equation, a = 6, b = 7, and c = 50.

Plugging these values into the quadratic formula, we get:

x = (-7 ± √(7² - 4 * 6 * 50)) / (2 * 6)

Simplifying further, we have:

x = (-7 ± √(49 - 1200)) / 12

x = (-7 ± √(-1151)) / 12

The term inside the square root, -1151, is negative. This means that there are no real solutions to the equation 6x² + 7x + 50.

Therefore, there are no solutions from the given options A, B, C, D, E, and F.