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Suppose that $3,000 is invested at a rate of 6.2% . Assuming that no withdrawals are made, set up the

equation (do not evaluate), which will give the total amount after 4 years if interest is compounded
(6 pts.)
a. Annually
b. Quarterly
c. Monthly
d. Continuously
= 2
HA: = 0

User Levi Putna
by
7.2k points

1 Answer

3 votes

Answer:

Sure, I'd be happy to help!

The equation for the total amount after 4 years, assuming an interest rate of 6.2% and compounding:

$$

A = P \times (1 + r/n)^(n\times t)

$$

Where:

A = Total amount after 4 years

P = Principal amount of $3,000

r = Interest rate of 6.2%

n = Number of times interest is compounded per year

t = Time in years (4 years in this case)

Now, we need to determine the value of n, which depends on the compounding frequency.

a. Annually:

n = 1 (since interest is compounded once a year)

b. Quarterly:

n = 4 (since interest is compounded once a quarter)

c. Monthly:

n = 12 (since interest is compounded once a month)

d. Continuously:

n = ∞ (since interest is compounded continuously)

So, the equation for the total amount after 4 years, assuming an interest rate of 6.2% and compounding:

$$

A = 3,000 \times (1 + 0.062/1)^(1\times 4) = 3,000 \times 1.248 = 3,744

$$

Total amount after 4 years: $3,744

Explanation:

User Tom Alabaster
by
6.9k points