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NEED HELP ASAP

Given PT is an angle Bisector of m <1 = 7x + 7
What’s the
x=
<1=

NEED HELP ASAP Given PT is an angle Bisector of m <1 = 7x + 7 What’s the x= &lt-example-1
User Spivonious
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6 votes

Answer:

Hello! I'm here to help you with your question. To start, I'll need to clarify that the equation you provided, m <1 = 7x + 7, is not a correct mathematical expression. The symbol "<" is not a valid mathematical operator, and the equation does not make sense.

However, if you meant to ask for the value of x in the equation 7x + 7 = m, where m is an angle bisector of ∠PT, then we can solve for x using basic trigonometry.

First, let's draw a diagram of the situation:

In this diagram, we can see that ∠PT is an angle bisected by the line m. This means that the angle ∠PT is equal to half of its supplementary angle, which is ∠QTR.

Using the trigonometric identity sin(a + b) = sin(a)cos(b) + cos(a)sin(b), we can find the length of the side opposite angle ∠PT:

sin(∠PT) = sin(∠QTR / 2)

Now, we can use the fact that sin(∠QTR / 2) = 7x + 7 to find the value of x:

7x + 7 = sin(∠PT)

Simplifying the equation, we get:

7x + 7 = sin(∠QTR / 2)

Solving for x, we get:

x = (7 / 2)sin(∠QTR / 2)

Therefore, the value of x is:

x = 7 / 2sin(∠QTR / 2)

Explanation:

User Shaun Dychko
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