66.1k views
0 votes
The function graphed above is:

Concave up on the intervals:
Concave down on the intervals:
there is a reflection point at:

The function graphed above is: Concave up on the intervals: Concave down on the intervals-example-1
User Bonnopc
by
7.3k points

1 Answer

2 votes

Answer:

The function graphed above is a parabola, specifically a downward-opening parabola. This means that the function is concave down on the intervals [0,1] and [1,2], and concave up on the interval [2,3].

There is a reflection point at the point (1,2), where the graph of the function reflects over the x-axis.

Explanation:

User Jfunk
by
7.6k points