Question

Kevin accelerates his skateboard along a straight path from rest to 15 m/s in 2 s. a. What is Kevin's acceleration? b. What is Kevin's displacement during this time interval? c. What is Kevin's average velocity during this time interval?​

Answer 1

Step-by-step explanation:

u= 0m/s

v=15m/s

t=2s

`1.a = (v - u)/(t) \\ = (15 - 0)/(2) \\ = 7.5ms {}^( - 2) \\ s = ut + (1)/(2) * at {}^(2) \\ = 0(2) + (1)/(2) * 7.5(2) {}^(2) \\ = 15m \\ 3. = (displacement)/(time) \\ = (15)/(2) \\ = 7.5ms {}^( - 2)`

15/2=7.5m/s therefore average velocity=7.5m/s