Question

Directions - Graph the following slope intercept equation:y=-1/3x+4

Answer 1

See below for graph

Step-by-step explanation:

Given the slope-intercept equation:

`y=-(1)/(3)x+4`

To graph it, first, we find the x and y-intercepts.

When x=0

`\begin{gathered} y=-(1)/(3)(0)+4 \\ y=4 \end{gathered}`

We have the point (0,4).

When y=0

`\begin{gathered} 0=-(1)/(3)x+4 \\ (1)/(3)x=4 \\ x=12 \end{gathered}`

We have the point (12,0).

We then draw a line joining points (0,4) and (12,0).