Answer:
The vector parametric equation of the line through the points P=$(−4,2,4)$ and $Q=$(−4,−3,5)$ is given by:
$$r(t) = (−4 + 2t, 2 + t, 4 + 3t)$$
Step-by-step explanation:
To find the vector parametric equation of the line, we need to find the difference between the two points and express it as a function of the parameter t. Let's call the difference vector $\mathbf{d} = P - Q$. We have:
$$\mathbf{d} = (−4, −3, 5) - (−4, 2, 4) = (−7, 1, 1)$$
Now, we can write the vector parametric equation of the line as:
$$r(t) = P + t\mathbf{d} = (−4, 2, 4) + t(-7, 1, 1) = (−4 + 2t, 2 + t, 4 + 3t)$$
Note that $r(0) = P$ and $r(2) = Q$, so the equation satisfies the given conditions.
Step-by-step explanation: