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The graph shows the daily revenue earned selling coupon cards in a fundraiser if the price is decreased by x dollars. Which function can be used to determine the daily revenue if the price of a coupon card is decreased by x dollars? R(x) = –x2 + 6x + 40 R(x) = –(x – 4)(x + 10) R(x) = –(x2 – 14x + 40) R(x) = –(x + 3)2 + 49

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User Kandii
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1 Answer

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Answer:

Explanation:

R(x) = -x^2 + 6x + 40

R(x) = -(x - 4)(x + 10)

R(x) = -(x^2 - 14x + 40)

R(x) = -(x + 3)^2 + 49


R(x) = -x^2 + 6x + 40

This option represents a quadratic function of x, but it doesn't directly involve a decrease in price. It's unlikely to be the correct choice.

R(x) = -(x - 4)(x + 10)

This option represents a quadratic function of x, and it does involve a decrease in price (x - 4), so it seems to be a better choice.

R(x) = -(x^2 - 14x + 40)

This option represents a quadratic function of x, but it does not directly involve a decrease in price. It's unlikely to be the correct choice.

R(x) = -(x + 3)^2 + 49

This option represents a quadratic function of x, but it involves an increase in price (x + 3) rather than a decrease. It's also unlikely to be the correct choice.

User Murillo Ferreira
by
8.2k points

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