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I’ve just made 1.50 L of a 0.65 M solution, using 2.3 mL of stock. What was the concentration of the stock?

User Fayeure
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1 Answer

3 votes

Answer:

To determine the concentration of the stock solution, we can use the formula:

C1V1 = C2V2

Where:

C1 = concentration of the stock solution

V1 = volume of the stock solution used

C2 = concentration of the final solution

V2 = volume of the final solution

In this case, we have:

C1 = ?

V1 = 2.3 mL

C2 = 0.65 M

V2 = 1.50 L

First, we need to convert the volume of the stock solution from milliliters (mL) to liters (L):

V1 = 2.3 mL ÷ 1000 mL/L

V1 = 0.0023 L

Now, we can rearrange the formula to solve for C1:

C1 = (C2 * V2) / V1

C1 = (0.65 M * 1.50 L) / 0.0023 L

Calculating this expression gives us:

C1 ≈ 423.91 M

Therefore, the concentration of the stock solution is approximately 423.91 M.

Step-by-step explanation:

User Djsly
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