Answer:
the probability of a couple having exactly 1 boy out of 3 children is 3/8.
Explanation:
To find the probability that a couple will have exactly 1 boy out of 3 children when boys and girls are equally likely, you can use combinations.
The total number of possible outcomes for each child (boy or girl) is 2, and you have 3 children, so there are 2^3 = 8 possible outcomes in total.
Now, let's consider the different ways to have exactly 1 boy out of 3 children. This can happen in three ways: BGG, GBG, or GGB, where "B" represents a boy, and "G" represents a girl.
So, the probability of having exactly 1 boy is:
(Number of favorable outcomes) / (Total number of possible outcomes)
= 3 (BGG, GBG, GGB) / 8 (total possible outcomes)
= 3/8
Therefore, the probability of a couple having exactly 1 boy out of 3 children is 3/8.