Question

if you cross two heterozygous, but homozygous dominant lead, the what would the expected phenotypic ratio be assumed dominant aliyah is black for recessive allele is white fur

Answer 1

To determine the expected phenotypic ratio when crossing two heterozygous individuals for a single trait, you can use a Punnett square. In this case, both parents are heterozygous for a single gene responsible for fur color, with the dominant allele (A) leading to black fur and the recessive allele (a) leading to white fur. Here's the Punnett square for this cross:

Parent 1 (heterozygous): Aa (black fur)

Parent 2 (heterozygous): Aa (black fur)

The possible combinations of their alleles are:

- AA (black fur)

- Aa (black fur)

- Aa (black fur)

- aa (white fur)

So, the expected phenotypic ratio is 3 (black fur) to 1 (white fur). This means that if you were to cross two heterozygous individuals, you would expect approximately 75% of their offspring to have black fur (dominant phenotype) and 25% to have white fur (recessive phenotype).