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12 votes
5. Find the equation of a line that is parallel to y = 2x + 8 and passes through (5, 1).

5. Find the equation of a line that is parallel to y = 2x + 8 and passes through (5, 1).-example-1
User Huzle
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1 Answer

18 votes
18 votes

First, let's find the slope of the given line, comparing the equation with the slope-intercept form of a linear equation (y = mx + b, where m is the slope).

Looking at the equation, we have m = 2.

Since parallel lines have the same slope, so the slope of the parallel line is also m = 2.

Then, using the point (5, 1) in the equation, we have:


\begin{gathered} y=mx+b \\ 1=2\cdot5+b \\ 1=10+b \\ b=1-10 \\ b=-9 \end{gathered}

Therefore the equation is y = 2x - 9, and the correct option is 1.

User Siddhu
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2.9k points
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