Question

x Match each situation with its solution. Terms Two payment options to rent a car: You can pay $20 a day plus 25¢ a mile (Option A) or pay $10 a day plus 50¢ a mile (Option B). For what amount of daily miles will option A be the cheaper plan? Two payment options to rent a car. You can pay $25 a day plus 30c a mile. (Option A) or pay $15 a day plus 80¢ a mile (Option B). For what amount of daily miles will option A be the cheaper plan? Two payment options to rent a car: You can pay $30 a day plus 10c a mile (Option A) or pay $10 a day plus 50¢ a mile (Option B). For what amount of daily miles will option A be the cheaper plan? Two payment options to rent a car. You can pay $20 a day plus 10¢ a mile (Option A) or pay $10 a day plus 30¢ a mile (Option B). For what amount of daily miles will option B be the cheaper plan? Two payment options to rent a car. You can pay $20 a day plus 10¢ a mile (Option A) or pay $10 a day plus 50c a mile (Option B). For what amount of daily miles will option B be the cheaper plan? Two payment options to rent a car. You can pay $25 a day plus 5¢ a mile (Option A) or pay $15 a day plus 30c a mile (Option B). For what amount of daily miles will option B be the cheaper plan? :: x < 25 :: x > 40 IT 11 :: X < 40 :: X > 50 :: x > 20 :: X < 50 5 of 10​

Answer 1

Answer: Situation 1: x > 40

Situation 2: x < 40

Situation 3: x < 50

Situation 4: x > 20

Situation 5: x > 50

Situation 6: x > 50

Step-by-step explanation: To find the amount of daily miles that make one option cheaper than the other, we need to set up an inequality and solve for x, where x is the number of miles driven per day.

For example, for the first situation, we have:

20+0.25x<10+0.5x

We subtract 10 from both sides and get:

10+0.25x<0.5x

We subtract 0.25x from both sides and get:

10<0.25x

We divide both sides by 0.25 and get:

40<x

This means that option A is cheaper than option B when x is greater than 40 miles per day.

We can apply the same method to the other situations and get the following results:

For the second situation, option A is cheaper than option B when x is less than 40 miles per day.

For the third situation, option A is cheaper than option B when x is less than 50 miles per day.

For the fourth situation, option B is cheaper than option A when x is greater than 20 miles per day.

For the fifth situation, option B is cheaper than option A when x is greater than 50 miles per day.

For the sixth situation, option B is cheaper than option A when x is greater than 50 miles per day.

Therefore, the correct matches are:

Situation 1: x > 40

Situation 2: x < 40

Situation 3: x < 50

Situation 4: x > 20

Situation 5: x > 50

Situation 6: x > 50