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What is an equation of the line that passes through the points (3,3) and (-1,7)

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4 votes

Answer:

y=-x+6

Explanation:

We'll use the point-slope form of a linear equation:

\(y - y_1 = m(x - x_1)\)

Where \(m\) is the slope, and \((x_1, y_1)\) is a point on the line.

First, calculate the slope (m):

\(m = \frac{y_2 - y_1}{x_2 - x_1} = \frac{7 - 3}{-1 - 3} = \frac{4}{-4} = -1\)

Now that we have the slope, we can choose either of the two points to plug into the equation. Let's use (3,3):

\(y - 3 = -1(x - 3)\)

Now, simplify:

\(y - 3 = -x + 3\)

Add 3 to both sides:

\(y = -x + 6\)

So, the equation of the line is \(y = -x + 6\).

User Qurban
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