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The weights of the melons harvested from a patch are distributed normally. The mean weight is 6 pounds; the standard deviation is 0.25 pounds. Which is closest to the percent of melons that weigh 6.25 pounds or less?A) 34B) 68C) 84D) 98

User Javiera
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1 Answer

18 votes
18 votes

As it is normally distributed, we can use Z to find the result.

Procedure

0. Finding the value of ,Z


Z=(x-\mu)/(\sigma)

1.2. Replacing the values given in the problem:


Z=(6.25-6)/(0.25)
Z=(0.25)/(0.25)=1

2. As it is normally distributed:


P(x\le6.25)=P(Z\le1)

3. Using the normal standard table, we can conclude:


P(Z<1)=0.8413

As it is asking for a percentage, we multiply by 100.

Answer: C) 84%

User AshleyWilkes
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