Question

What is the temperature change when 69.0kJ is transferred to a 1.20kg object with a specific heat capacity of 250J/(kg ∘ C)?

Answer 1

ΔQ = C M ΔT where ΔQ is heat transferred

ΔT = ΔQ / (C M)

ΔT = 6.9E4 J / (250 J / kg * 1.2 kg / deg C)

ΔT = 69000 / (250 * 1.2) / deg C = 230 deg C