Answer:
To find the equation of the line that passes through the points (0, 2) and (-1, 0), you can use the point-slope form of the equation of a line:
y-y1=m(x-x1)
where:
x1 and y1 are the coordinates of one of the points on the line
m is the slope of the line
first calculate the slope, m, using two points (0,2) and (-1,0)
m = 0-2 / -1-0 = -2 / -1 = 2
Now, plug in the values of one of the points (let's use (0, 2)) into the point-slope equation:
y - 2 = 2(x-0)
simplify :
y - 2 = 2x
Now, isolate y to get the equation in slope-intercept form (y = mx + c)
y =2x +2