Question

I need help plsssssss :(

Answer 1

Hi there!

We are asked to find the slope and a point on this line.

To do this, we need to consider the form of the equation. In this case, it's point slope.

Point slope is:

`\boldsymbol{y-y_1=m(x-x_1)}`

where m is the slope and (x1, y1) is the point.

Our equation is:

`\boldsymbol{y+5=\cfrac{1}{4}(x-3)}`

Slope: 1/4

Point: (3, -5)

check our answer

Write an equation with the data.

`\boldsymbol{y-(-5)=\cfrac{1}{4}(x-3)}`

Which simplifies to...

`\boldsymbol{y+5=\cfrac{1}{4}(x-3)}`

Therefore, the slope is 1/4 and the point is (3,-5).

<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<

Best wishes!

Answer 2

1/4 slope (0, -23/4)

Explanation:

First, let’s simplify the equation:

y + 5 = 1/4(x - 3)

Move 5

y = 1/4(x - 3) - 5

multiply 1/4 in parenthesis.

y = 1/4x - 3/4 - 5

y = 1/4x - 23/4

Now we can see that the slope of the line is 1/4, and a point on the line is (0, -23/4).

I hope my explanation is clear. :D