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Ia x+2 a factor of x^3+8

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Yes!

To determine if x + 2 is a factor of x^3 + 8, you can use the factor theorem.

The factor theorem states that if you substitute the root of a potential factor into the polynomial, the result should be equal to zero.

In this case, you need to check whether x + 2 is a factor of x^3 + 8 by setting x = -2: (-2)^3 + 8 = -8 + 8 = 0.

Since substituting x = -2 results in the polynomial equaling zero, x + 2 is indeed a factor of x^3 + 8.

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