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"Find the values for a and b that would make the equality true. -2y(y– 6y - 3) = ay} + 12y2 + by a= b="

User Nag Raj
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1 Answer

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The values for a and b that make the equality true, let's simplify the equation and solve the system of equations obtained by grouping the terms. The values for a and b that make the equality true are a = -2 and b = 8.

The corrected equation is -
2y(y - 6y - 3) = ay + 12y^2 + by.

To find the values for a and b that make the equality true, let's simplify the equation:


-2y(-5y - 3) = ay + 12y^2 + by

Distribute the -2y on the left side:


10y^2 + 6y = ay + 12y^2 + by

Now, let's group the terms:


10y^2 + 6y = (a + 12)y^2 + (a + b)y

For the equality to hold true, the coefficients of corresponding powers of y on both sides must be equal. This gives us a system of equations:

Coefficients of
y^2: 10 = a + 12

Coefficients of
y: 6 = a + b

Solving these two equations will give us the values for a and b:

a + 12 = 10 ⟶ a = -2

a + b = 6 ⟶ -2 + b = 6 ⟶ b = 8

Therefore, the values for a and b that make the equality true are

a = -2 and b = 8.

User Siya
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