49.8k views
1 vote
A garden has an area of 280ft². Its length is 6ft more than its width. What are the dimensions of the garden?

1 Answer

2 votes

Answer:

length = 20 ft , width = 14 ft

Explanation:

the area (A) of a rectangle (garden ) is calculated as

A = length × width

let width be w , then length = w + 6 ( 6 ft more than width )

given A = 280 ft² , then

280 = w(w + 6) = w² + 6w ( subtract 280 from both sides )

0 = w² + 6w - 280 ← quadratic equation in standard form

consider the factors of the constant term (- 280) which sum to give the coefficient of the w- term (+ 6)

the factors are + 20 and - 14 , since

+ 20 × - 14 = - 280 and + 20 - 14 = + 6

use these factors to split the w- term

w² + 20w - 14w - 280 = 0 ( factor the first/second and third/fourth terms )

w(w + 20) - 14(w + 20) = 0 ← factor out (w + 20) from both terms

(w + 20)(w - 14) = 0 ← in factored form

equate each factor to zero and solve for w

w + 20 = 0 ⇒ w = - 20

w - 14 = 0 ⇒ w = 14

but w > 0 , then w = 14 and w + 6 = 14 + 6 = 20

length = 20 ft and width = 14 ft

User Albarji
by
7.5k points