Question

I need help finding the area for these acceleration time graphs problem C.

Answer 1

We are given that an object starts with an initial velocity of 5 m/s and that we are required to determine its velocity after 2 seconds. We are given the area of acceleration vs time. In a graph of acceleration vs time, the area under the curve represents the velocity of the object under the given acceleration.

We can determine the velocity reached by the object between t = 0 and t = 2 finding the area under the curve. Since the acceleration is constant the area under the curve is a square, therefore:

`v=(2(m)/(s^2))(2s)=4(m)/(s)`

This is the velocity after the object starts accelerating the final velocity is determined by adding the initial velocity therefore, the final velocity is:

`v_f=4(m)/(s)+5(m)/(s)=9(m)/(s)`