Answer
Volume of O2 = 1326 L
Step-by-step explanation
Given:
2C8H18(I) + 25 O2 (g) = 16 CO2(g) + 18 H2O (g)
moles of gasoline = 4.00 mol
Pressure = 0.953 atm
Temperature = 35 C = 308 K
Required: volume of oxygen
Solution
Step 1: use stoichiometry to find the moles of oxygen
The molar ratio between gasoline and O2 is 2:25
Therefore the moles of o2 = 4.0 mol x (25/2) = 50.0 mol
Step 2: Calculate the volume using ideal gas law
PV = nRT
V = nRT/P
V = (50.0 x 0,08206 x 308)/0.953
V = 1326 L