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Write down the first five terms of the sequence an=(n+4)!2n2+6n+7a1 = a2 = a3 = a4 = a5 =

Write down the first five terms of the sequence an=(n+4)!2n2+6n+7a1 = a2 = a3 = a-example-1
User Robert Co
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1 Answer

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7 votes

Step 1

Given;


\begin{gathered} a_n=((n+4)!)/(2n^2+6n+7) \\ n=1,2,3,4,5 \end{gathered}

Step 2


a_1=((1+4)!)/(2(1)^2+6(1)+7)=(120)/(15)=8
a_2=((2+4)!)/(2(2)^2+6(2)+7)=(720)/(27)=(80)/(3)
a_3=((3+4)!)/(2(3)^2+6(3)+7)=(5040)/(43)
a_4=((4+4)!)/(2(4)^2+6(4)+7)=(8!)/(63)=640
a_5=((5+4)!)/(2(5)^2+6(5)+7)=(9!)/(87)=(120960)/(29)

User Kyle Cordes
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