Let f(x) = ax ² + bx + c. Then
f '(x) = 2ax + b
f ''(x) = 2a
f (-3) = -18, so
9a - 3b + c = -18
f ' (-3) = 16, so
-6a + b = 16
f '' (-3) = -6, so
2a = -6
Then a = -3, b = -2, and c = 3, so that
f(x) = -3x ² - 2x + 3
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