Final answer:
The major product of the reaction between 2-bromo-2-methylbutane and an acetylide ion is 3,3-dimethylpent-1-yne.
Step-by-step explanation:
The major organic product formed when 2-bromo-2-methylbutane reacts with an acetylide ion is a nucleophilic substitution reaction, where the acetylide ion, a strong nucleophile, displaces the bromide ion from the 2-bromo-2-methylbutane. Considering that the acetylide ion has a negative charge and acts as a good nucleophile, it will attack the carbon that is connected to the bromide, leading to the formation of a new carbon-carbon triple bond.
Therefore, the major product of this reaction will be 3,3-dimethylpent-1-yne, which corresponds to option (a) in the given question. Other options like 2-methylbut-2-ene ethyne, 2-methylbut-1-ene, or 'no reaction' do not accurately represent the expected outcome of the reaction conditions presented in the question.