Final answer:
To find the time it takes for a car to stop, we can use the equation v = u + at, where v is the final velocity (0 m/s in this case), u is the initial velocity (-5.00 m/s), a is the acceleration, and t is the time. Since the car is slowing down, the acceleration is negative. Plugging in the values, we get t = (0 - (-5.00)) / (-1.67) = 3 seconds.
Step-by-step explanation:
To find the time it takes for a car to stop, we can use the equation v = u + at, where v is the final velocity (0 m/s in this case), u is the initial velocity (-5.00 m/s), a is the acceleration, and t is the time. Since the car is slowing down, the acceleration is negative.
First, we need to find the acceleration. We can use the equation v^2 = u^2 + 2as, where v is the final velocity (0 m/s), u is the initial velocity (-5.00 m/s), a is the acceleration, and s is the distance (15.0 m). Rearranging the equation, we have a = (v^2 - u^2) / (2s).
Plugging in the values, we get a = (0^2 - (-5.00)^2) / (2*15.0) = -1.67 m/s^2.
Now, we can use the equation v = u + at to find the time, t. Rearranging the equation, we have t = (v - u) / a. Plugging in the values, we get t = (0 - (-5.00)) / (-1.67) = 3 seconds.