Question

given that triangle DEF is a right triangle with acute angles D and F and right angle E, which trigonometric function would be equal to Sin(F).

Answer 1

EXPLANATION

We can represent this situation as shown as follows:

The expression of Sin(F) is equal to Sin F = Opposite/Hypotenuse = DE/DF

`\sin F=\frac{Opposite}{\text{Hypotenuse}}=(DE)/(DF)`

The equivalent expression would be:

`Cos\text{ D=}\frac{Adjacent}{\text{Hypotenuse}}=(DE)/(DF)`