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Solve the problem. A cashier has a total of 135 bills, made up of fives and tens. The total value of the money is $745. How many ten-dollar bills does the cashier have?​

User AWB
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Answer:

the cashier has 14 ten-dollar bills.

Explanation:

Let x be the number of ten-dollar bills.

Then the number of five-dollar bills is 135 - x.

The total value of the ten-dollar bills is 10x.

The total value of the five-dollar bills is 5(135 - x).

The total value of all the bills is 10x + 5(135 - x) = 745.

Combining like terms, we get 5x + 675 = 745.

Subtracting 675 from both sides, we get 5x = 70.

Dividing both sides by 5, we get x = 14.

Therefore, the cashier has 14 ten-dollar bills.

User Harunurhan
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