Final answer:
The sum of the first 50 even numbers is 5000. The digit at the ones place of the number obtained by multiplying 4, 100 times is 4.
Step-by-step explanation:
To find the sum of the first 50 even numbers, we need to understand that even numbers are those that are divisible by 2. The sum of the first 50 odd numbers is 2500, so we can conclude that each odd number contributes 50 to the total sum. Since even numbers are 2 times greater than odd numbers, the sum of the first 50 even numbers would be 2 times the sum of the first 50 odd numbers.
The sum of the first 50 even numbers would be 2 * 2500 = 5000.
To find the digit at the ones place of the number obtained by multiplying 4, 100 times, we need to understand the pattern that occurs when we multiply 4 with increasing powers of 10. When we multiply any number by 10, the ones place digit becomes 0. So, the digit at the ones place remains the same when we multiply by higher powers of 10. Therefore, if we multiply 4 by 10, 100, or even 1000 times, the digit at the ones place would still be 4.
Learn more about Sum of even numbers, Multiplication with powers of 10